If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2-16x-64=0
a = 8; b = -16; c = -64;
Δ = b2-4ac
Δ = -162-4·8·(-64)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-48}{2*8}=\frac{-32}{16} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+48}{2*8}=\frac{64}{16} =4 $
| 6(6n+5)=5(8n+10) | | (t+8)(-2)=1.8 | | a÷6+6=11 | | 1/8x+5=6 | | 10x-1-3x-5=8 | | 1/3+c=5/3 | | X-20/x+280=x | | 2x+4-(-3x+2)=0 | | 45+8s=88 | | 2x+24=6x+89099767865736 | | 6x-22=-58 | | x+5=5/2x-4=3 | | −2x+8=−0 | | (3n+3)/3=9 | | y+1/9=2/5 | | x+5=5/3 | | 3x+5x=15.2 | | 3/5=10/x-3 | | (2x-5)(x-7)=2 | | 3*3x+4x/10=1 | | 15x+20=5x+320 | | 2−4a=16 | | F(n)=n+12 | | 3*3x+4x=12 | | 5+11x=-5x | | -4.5=-0.1(x-7.1) | | 0.5(4x+8)=5(2x-4) | | |2p-5|=9 | | v/2=34 | | 3*3*x+4x=12 | | 7y–83°=2y+7° | | -20=4w-4 |